Under the action of a force a 2 kg body

Author: jaid

August undefined, 2024

WebTranscribed Image Text: Under the action of a force, a 2 kg body moves such that its position x as a function of timet is given by x = where x 3 is in metre andt in second. The work done by the force in the first two seconds is (a) 1600 J (c) 16 J (b) 160 J (d) 1.6 J WebTwo forces act on a 2.55 kg object, the gravitational force and a second, constant force. The object starts from rest and in 1.20 s is displaced (4.05î – 3.30j) m. Write the second force …

Under action of force, a 2 kg body moves such that its position x …

WebMar 25, 2024 · Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x = (t^ (3))/ (3) where x is in metre and t in second. The work … WebApr 26, 2024 · A body of mass 4 kg moves under the action of a force vector F = (4i + 12t 2 j)N, where t is the time in second. The initial velocity of the particle is (2i + j + 2k) ms-1.If the force is applied for 1 s, work done is : geniposide solubility in water

A body moves from point A to B under the action of a force

WebQ: Under the action of force 2 kg body moves such that its position ‘x’ varies as a function of time t given by x= t 3 /3, x is the meter and t in second. Calculate the workdone by the … WebApr 10, 2024 · The optimized control parameters and motion models were applied to the experimental prototype for testing. The maximum load limit of a single knee joint under 10 MPa system pressure is 24 kg. The foot force of squatting, walking, landing and buffering with a weight of 20 kg is less than 400N, and there is no obvious damage to the joint. WebApr 11, 2024 · A body of mass 1 kg begins to move under the action of time dependent force F → = ( 2 t i ^ + 3 t 2 j ^) N Where i ^ and j ^ are unit vectors along x and y axes. What power will be developed by the force at the time, t? (A) ( 2 t 2 + 3 t 2) W (B) ( 2 t 4 + 4 t 4) W (C) ( 2 t 3 + 3 t 4) W (D) ( 2 t 3 + 3 t 5) W Last updated date: 25th Mar 2024 • gen-ip solutions

Under the action of force, a 2 kg body moves such that x …

Answered: Two forces act on a 2.55 kg object, the… bartleby

WebASK AN EXPERT. Math Advanced Math A body with an initial mass of 200Kg is in motion under the action of a constant force of 2000N. Knowing that this body is losing 1 kg of its mass per second and considering that the air resistance is twice its speed and that the body is at rest at time t = 0, then the ordinary differential equation that ... WebUnder action of force, a 2kg body moves such that its position x as function of time t is given by x = αt2/2 where x is in meters, t is in seconds and α = 1m/s2. The work done by … genipin solubility in waterWebUnder the action of a force, a 2 kg body moves such that its position x as a function of time t is given by x = t 3/3, where x is in meter and t in second. The work done by the force in the … gen iptv professional

"WebAug 8, 2024 · Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x = t3/3 where x is in metre and t in second. The work done by … " - Under the action of a force a 2 kg body

Under the action of a force a 2 kg body

The relation between displacement x and time, t for a body of mass 2 kg …

WebUnder the action of a force, a 2 kg body moves such that its position x as a function of time t is given by x= t3 3, where x is in meter and t in second. The work done by the force in the first two seconds is Q. The distance x moved by a body of mass 0.5 kg due to a force varies with time t as x=3t2+4t+5 WebUnder the action of a force, a 2 kg body moves such that its position x as a function of time t is given by x = t 3 3 , where x is in meter and t in seconds. The work done by the force in the first two seconds is: Numericals based on work energy theorem.

Did you know?

WebJul 12, 2024 · Under the action of a force, a `2 kg` body moves such that its position x as a function of time is given by `x =(t^(3))/(3)` where x is in metre and t in sec... AboutPressCopyrightContact... WebMar 28, 2024 · The correct answer is 490J CONCEPT: Work-energy theorem: It states that the sum of work done by all the forces acting on a body is equal to the change in the kinetic energy of the body i.e., Work done by all the forces = K f - K i W = 1 2 m v 2 − 1 2 m u 2 = Δ K Where v = final velocity, u = initial velocity and m = mass of the body CALCULATION:

WebSep 3, 2024 · Under the action of a force, a 2 kg body moves - such that its position x as a function of time t is given by x= t^2/3, where x is in metre and t in second. The work done … WebUnder the action of a force, a 2 kg body moves such that its position x in meters as a function of time t in seconds given by: x=t 2/2. The work done by the force in the first 5 …

WebApr 14, 2024 · Zambia, Africa, shortage, sport 1.8K views, 91 likes, 4 loves, 13 comments, 2 shares, Facebook Watch Videos from Camnet TV: HEADLINES 1. RICE AND MILLET RECORD A SHARP RISE AMIDST MEALIE MEAL... WebIf the body shown in the illustration is a homogeneous disc, this moment of inertia is = /. If the disc has the mass 0,5 kg and the radius 0,8 m, the moment of inertia is 0,16 kgm 2. If the amount of force is 2 N, and the lever arm 0,6 m, the amount of torque is 1,2 Nm.

WebApr 8, 2024 · Abstract Computer algebra methods are used to determine the equilibrium orientations of a system of two bodies connected by a spherical hinge that moves in a central Newtonian force field on a circular orbit under the action of gravitational torque. Primary attention is given to the study of equilibrium orientations of the two-body system …

WebClick here👆to get an answer to your question ️ A rigid body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1 thenWork done by the applied force on the body in 10 s. chowking uncianoWebMay 24, 2024 · A body moves from point A to B under the action of a force, varying in magnitude as shown in figure. Obtain the work done. Force is expressed in newton and displacement in meter. class-11 work power-&-energy Share It On 1 Answer 0 votes answered May 24, 2024 by Pankajsingh (87.1k points) selected May 24, 2024 by … chowking supply chain managementWebAug 4, 2024 · Under the action of a force, a \\( 2 \\mathrm{~kg} \\) body moves such that its position \\( x \\) as a function of time is given by \\( x=t^{3} / 3 \\) where \\( x ... chowking sweet and sour fishWebAnswer (1 of 4): The only way to answer your question is to assume that the body is “at rest” on a horizontal frictionless surface, or is a free body in space, not under the influence of any other forces (such as gravitation) but the one given. … chowking total slexWebMar 20, 2024 · Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x = 3 t 3 , where x is in metre and t in second. The work done by the force in the first two seconds is geni robert the bruceWebInformation about Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x = t3/3, where x is in meters and t is in sec. The work done … chowking swot analysisWebApr 8, 2024 · Hint: We are given that the mass of the body is 2 kg but in order to find out the force, we need to have the acceleration.We are given a relationship between the displacement and the time. We can differentiate this equation to find a relationship between the differentials and then we can integrate it to find out the velocity and then the … chowking tuguegarao delivery number